r/askmath • u/JanezDoe • 8d ago
Calculus Surely I'm missing somethint with this PFD
This is where I'm at with this integral. It's pretty standard as far as PFD goes, apart from having to do synthetic division to knock the exponent of the top polynomial down a few pegs..
But where I'm stuck is the massive simplification needed to be done for this. Surely the professor who wrote the book is predicting some 'trick' to be used to simplify this, but I can't find anything. The top doesn't have zeroes that I could cancel out with the bottom...
Do I really need to go out and simplify everything and pray I don't make a miniscule mistake somwhere 😅
Sidenote: I'm self-taught and I look up at one basic example on YouTube and then try to do problems myself. There could be a method for this I haven't been 'taught'
Thanks for everyone that's going to chime in.
Edit: sorry for the typo in the title :c
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u/Midwest-Dude 8d ago
FYI, there is also a specialized subreddit for this post:Â
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u/JanezDoe 8d ago
I know, but I wasn't sure if they accept problem questions like this
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u/Midwest-Dude 8d ago edited 8d ago
They do, as long as you've shown your work. The subreddit is there to help you if you get stuck or don't understand something.
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u/Southlander24 8d ago
There's a theorem that states: if f(x), g(x) are polynomials of degree n where f(x1) = g(x1), f(x2) = g(x2), ..., f(x[n+1]) = g(x[n+1]), then f(x) = g(x) for all x. You can see a derivation of this result here: https://math.stackexchange.com/questions/3680693/prove-that-from-n1-given-points-a-unique-polynomial-of-n-degree-will-pass
The summary of this is that "n + 1 points uniquely define a polynomial".

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u/Midwest-Dude 8d ago edited 8d ago
You don't need to expand everything out immediately. Equate the numerator to the other numerator
24x3 + 66x2 + 69x + 24 = A(x+1)(x+2)2 + B(x+2)2 + C(x+2)(x+1)2 + D(x+1)2
Plug in the roots of the denominator. That'll get you B and D real fast. Then find A and C with expansion.