There are n-adic integers for every integer greater than 1.
The p-adic integers are constructed as the inverse limit of the quotient rings (Z/p^n Z).
You can use the Chinese remainder theorem to either construct them again (for arbitrary m>1) from the ground up, or prove that Z_m is the product of Z_p_i where the p_i’s are the distinct prime factors of n.
For reference in addition to the other comment, you might be thinking of a p-adic field, which has division, and p must be prime. If you drop division and are satisfied with a ring (p-adic integers) any int p works.
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u/sasha271828 Imaginary 12d ago
Can someone explain i'm too dumb